Ereg Quick help

Anon

if (ereg("^{$username$",$customerfile[$i]))} {

$founduser = split(":","$customerfile[$i]");

}

I want it to detect only the $username(nothing else before or after).

I am missing something easy here, I can feel it.

Anon

Are you trying to extract the username from the string? If so,

$user = ereg("^{$username$",$customerfile[$i]);}
If not your current code is splitting the string into the array $founduser by the delimiter ":" You would now need to access the part of the array you need by using:
$founduser[0]; or [1] wherever your username was in the string

Anon

I have an array of data in $customerfile[$i]

each array element is a line of code similar to the following format

username:info:info:info:etc

I then extract that line of code when found by ereg() and split it into it's own array.

then I use the $found[0],$found[1] etc,,,
l8r in my script.

problem being that right now I might enter in
"dave" as a username but it there is no user
dave then it might pick up "daveb".

I thought ("^$username$", would clear this up... but I must be doing something wrong.

Anon

Trying splitting the array first
like:

$founduser = explode(":", $customerfile[$i]);

Now you could test like:

if ($username == $founduser[0]) {

do something;

}
Your ereg will return true if the string contains any of $username

Hope that helps

Anon

Thanks for the help.. I just clued into something and it works.. I can't believe I didn't think of it. Just wasn't paying attention to what I was comparing.

I made a simple change

if (ereg("^{$username:",$customerfile[$i]))} {

$founduser = split(":","$customerfile[$i]");

}

I am sure you can spot it.

-pat

Anon

Nice one username must be followed by an \":\"