$f will get deleted

[Anon]

Hi,

my problem is that $f will get deleted if I klick on the link to show next entries.

$f ist from a form site (<input type="text" name="f" size="50">). The other variables
like $ort or $plz will not get deleted if I call this site twice.

here is the script:

echo "f=$f";
if (empty($offset)) {$offset=0;}
if ($f AND $ort AND !$nachname AND !$plz): $suche= "ort='$ort' AND
fach1='$f'"; $suche2= "fach1=$f&ort=$ort";endif;

$result = mysql_query("SELECT FROM arzt WHERE $suche");
$numrows = mysql_num_rows($result);
$results = mysql_query("SELECT FROM arzt WHERE $suche limit
$offset,$limit");

$pages=intval($numrows/$limit);
if ($numrows%$limit) {$pages++;}
if (!(($offset/$limit)==$pages-1) && $pages!=0)
{$newoffset=$offset+$limit; print "<a
href=\"$PHP_SELF?$suche2&offset=$newoffset\">show next entries</a>";}

Please can anyone help me?

bye,

Roland

[Anon]

If you're reloading the page by following the link (or by using the browser's reload feature), I don't see where you're passing the value of $f on to the next script.

From what I understand $f is set if you use the form submit button to get to the page in question. But I don't see, anywhere in your code, where you would be passing it by any other means. My guess is that the place you want to change your script is this line:

print "<a href=\"$PHP_SELF?$suche2&offset=$newoffset\">show next entries</a>";}

so just add "&f=$f" and you should be fine.

HTH,

AC