bgcolor on every other table row

[Anon]

I'm generating a table out of MySQL, with an undetermined number of rows. I want to have every other row use a light gray background color, to make it easier to pick out data. How can I do this in PHP? Is there a way to do something like "if $i is odd, set this bgcolor..."? --thanks

[Anon]

Try this.

Before your while loop:

$cellcolor = array('#ffffff','#f5f5f5');
$color = 0;

Then in your while loop:

echo "<TR BGCOLOR=$cellcolor[$color]>... etc. etc.

Then before the end of the while loop:

if ("0"==$color){$color="1";}
else {$color="0";}

The close the while loop.

Should do the trick.

Darren

[Anon]

Randy,

I have a site that generates alternating row colors dynamically. "is_int" is good to use in this situation.

This is what the code looks like...

<?

$counter=0;

$linenumber=1;

do {

if (is_int($counter/2)):

$bgcolor="#eeeeee";

else:

$bgcolor="#ffffff";

endif;

[Anon]

how about combining the two solutions?
$backcolor = array ('#ffffff', '#f5f5f5');
$counter = 0;
then in your loop
echo "<TR BGCOLOR= $backcolor[bcmod($counter++,2)]>"

this requires the bcmath functions, I don't think there is a mod function in PHP4 otherwise but this should do the trick. Granted this is off the top of my head, and not tested but the logic is sound.

[Anon]

um maybe we're over-complicating this? What I've used many times with no problems is:

$counter = 2;

then in your loop:

if ($counter%2 == 0){ //or != 0 if you want to start with the other color
$color = "#somecolor";
}
else $color = "#someothercolor";

echo "<tr bgcolor=$color><td></td></tr>";