An AND in an IF

[Anon]

I know this is a very dumb question, but I can't find the answer. Why does this get me a parse error?

if(!($password = $row[password])) && (!($row[admin] != "yes")) {
...
}

I want to say, "If $password does not equal $row[password] AND $row[admin] does not equal yes, then bla. It gives me a parse error. Why? Thanks for your help.

[Anon]

Because you are closing the if before the &&. Try:

if ($password!=$row[password] && $row[admin] != "yes")

[Anon]

it should be:

if(($password != $row[password]) && ($row[admin] != "yes")) {
...
}

you were not using the brackets correctly.

and secondly if you are comparing something in IF or any other statement, you need comparisson, and thats == not =
singlw = sign makes it equal to what you tell it to. but double = sign are used for cpmparisson.