Passing Variables between pages

Anon

I have a web page taking data from a MySQL database and displaying it within a table. There are 3 sets of data each with a category id (1, 2 and 3). At the bottom of each table I have a hyperlink which popups a window displaying more data based upon the category id.

javascript:tccpopwindow('showrates.php3?ID=1', 415, 361)

The $ID variable should be available in the page that I pop up, do it is not. If open the page in the current browser window, it works.

Why is that?

How can I pass a value through to the form that I am poping up?

Any Help??????

Anon

Sure you can pass a variable that way. I'd first check to see if your pop-up box is really passing that variable to the page.

You can do that by

echo $REQUEST_URI at the top of the page. If ID is in there, you should be in good shape. If not, then your pop-up is messing up.

Anon

I am having a similar problem where the variables seems empty

ex : http://vempyre/php4.php?id=4

in the above exemple, if I echo the value of $id, "echo $id" it is empty, non-existant, why? shouldn't $id be defined as 4 by ?id=4 in the url?

I am following a tutorial on php/mysql in in their tutorial(webmonkey) this works very well(and it should, to my knowledge), but for some reason it doesn't work on my server

specs :
Win98
MySQL 3.23.21 Win32
PHP4.0.1pl2 Win32
PWS 4.0 or Apache 1.3.12 Win32(using both depending on mood)

I was reading the php.ini-opt file and it mentioned something about variables by reference or something that changed in php recently, would it be related to that?

Anon

echo " $id : this is the \$id variable echo test \n";

$db = mysql_connect("localhost", "root");

mysql_select_db("mydb",$db);

// display individual record

if ($id) {

$result = mysql_query("SELECT * FROM employees WHERE first=$id",$db);

$myrow = mysql_fetch_array($result);

printf("First name: %s\n ", $myrow["first"]);

printf("Last name: %s\n ", $myrow["last"]);

printf("Address: %s\n ", $myrow["address"]);

printf("Position: %s\n ", $myrow["position"]);

} else {

// show employee list

$result = mysql_query("SELECT * FROM employees",$db);

if ($myrow = mysql_fetch_array($result)) {

  // display list if there are records to display

  do {

    printf("<a href=\"%s?id=%s\">%s %s</a><br>\n", $PHP_SELF, $myrow["id"], $myrow["first"], $myrow["last"]);

  } while ($myrow = mysql_fetch_array($result));

} else {

  // no records to display

  echo "Sorry, no records were found!";	

}

}

Anon

I added :

$id = $HTTP_GET_VARS["id"];

to validate the data entry

but shouldn't it be done automatically?
must be a php.ini setting