Dynamically Including Files

Anon

I am trying to dynamically include .html files on my page based upon fields and paths that are generated from MySQL.

Ex.

Based upon the the $id and $file_name (any.html), I generate the appropriate include statement.

include ("/Data/$id/$file_name");

error: Warning: Failed opening '/Data/1/datapage.html' for inclusion .....

The html files are all located in different paths than the php script.

Is there any way to load the file without putting all of these different paths in the php_include_path (in php.ini)?

Note: Developing on PHP4 / Windows to be placed on UNIX/BSD.

Any help would be greatly appreciated,

Rich

Anon

By default php_include_path is set to "./" which would be the script's current directory. That could cause you problems the way you are spcifying include()'s because the script doing the include()'ing could be anywhere in the document tree, right?

If you change the default include path, say, to your document root directory, then you can always specify the file path relative to that no matter where the document is that is executing the include().

-- rich --

Anon

Thanks,

I tried to reconfigure the php.ini and I got close, but I have decided to just read the file directly since it is on the local filesystem anyway.

$fd = fopen("http://$server/Data/$id/$file", "r");

while (!feof($fd)) {
$buffer = fgets($fd, 4096);
echo $buffer;
}
fclose ($fd);

This approach works, but are there any security / performance risks?

Rich

Anon

...instead of using the "while" loop, you could just use the fpassthru() function to output the entire contents of the file. Also, be aware that with using these methods rather than "include()" you can not use the <?php and ?> directives to execute php in the files.

-- Rich Rijnders
-- Irvine, CA US