Cannot read ...

Anon

Hello

I am using the following code to copy a file from one directory to another:

<?php
// Upload photo files ...
if (isset($file_name) and $file_name != ""){
// upload file ... get extension first ...
$afile = basename($file_name);
$afile = explode (".", $afile);
end($afile);
$extension = current($afile);
$new_file_name = $DOCUMENT_ROOT."/".$id."_".$nomenclature.".".$extension;
if (is_readable($file_name)){
if (!copy($file_name, $new_file_name)) {
$e->errstr = "Could not copy file ".$file_name." to ".$new_file_name.".";
$e->method = "Upload";
}
}else{
$e->errstr = "File ".$file_name." is not readable.";
$e->method = "Upload";
}
}
}
?>

The variable $file_name is obtained from a form field with input type="file" under windows NT.

The piece of code is part of an application and it keeps returning the message that the FILE IS NOT READABLE. I have an Apache Linux setup and I have full rights to all directories, to read (from $file_name directory) and write (to $new_file_name directory).

Can anyone suggest what I could do to fix this problem ...

++Tx
Pete

Anon

try...
<?php
// Upload photo files ...
if (isset($file_name) and $file_name != ""){
// remove extra slashes from file
$afile = stripslashes("$afile");
// upload file ... get extension first ...
$afile = basename($file_name);
$afile = explode (".", $afile);
end($afile);
$extension = current($afile);
$new_file_name = $DOCUMENT_ROOT."/".$id."_".$nomenclature.".".$extension;
if (is_readable($file_name)){
if (!copy($file_name, $new_file_name)) {
$e->errstr = "Could not copy file ".$file_name." to ".$new_file_name.".";
$e->method = "Upload";
}
}else{
$e->errstr = "File ".$file_name." is not readable.";
$e->method = "Upload";
}
}
}
?>

Anon

Thank you for your reply ...

I had a go at stripslashes and unfortunately it did not work ... The only thing is did was remove the slashes and left me with the a string contianing the directory path and file name:

eg:
c:\directory\file_name.ext

became

c:directoryfile_name.ext

... do you have another suggestion ...

++Tx

Anon

have you tried echoing $new_file_name? If so, what does it give you... also where are the variables $id and $nomenclature defined?

thats all i see now... -g

Anon

$new_file_name gives me the file name entered in the form in the following format:

I enter
"C:\dir\file.ext"

echo gives the same:
"C:\dir\file.ext"

$nomenclature and the other variables are defined previously and are the new filename but I do not believe it has much to do with the problem ...

++Tx

Anon

This is solved by using a HTML form with attribute enctype="multipart/form-data". The variable for the file to be uploaded will have characteristics such as size, and name such that the variable $file submitted by the client will mean that the file name is stored in $file_name and size in $file_size ...

This can be found in the Professional PHP Programming Manual published by Wrox Inc. (I´m not sure if I am allowed to mention them here ...)

Anyway -g thanks for your help ...

++++Tx