Directory Size? - unix system cmd?

[Anon]

Is there a unix system command that I can access through php that will return the size of a directory including any and all sub-directories?

I'm pretty good with php these days, but I'm not much good when it comes unix so any help would really be appreciated.

thanks,
matt.

[Anon]

I am not sure about that but I have used php to satrt at one base directory add up the filesize of the files in that dir and any sub dirs beneath it. If you want to go that route let me know and I'll share how I did it.

[Anon]

Sure, that would be great. I'd be very interested to see how you've done it.

Thanks so much,
matt.

[Anon]

This one will work for one directory with several sub directories under it, if there are subdirs within the subdirs some tweaking may be necassary:

<?php
$basedir = "/home/something/www/";
chdir($basedir);
$dir = dir(".");
while ($file = $dir->read()) {
if (is_file($file)) {
$totalfilesize = $totalfilesize + filesize($file);
}
if (is_dir($file) && (($file != ".") && ($file != ".."))) {
$dirs[] = $file;
}
}

while (list ($key, $val) = each ($dirs)) {
chdir($basedir.$val);
$dir = dir(".");
while ($file = $dir->read()) {
if (is_file($file)) {
$totalfilesize = $totalfilesize + filesize($file);
}
}
chdir($basedir);
}

print "total file size= " . number_format(($totalfilesize / 1000), 2) ." kb";

?>

[Anon]

I am no sure I understand your question but I think du will fit your needs (man du)

Try 'du -sk directory name'

-rob

[Anon]

I just created a PHP version of du, give it a try:

Enjoy!

function du($dirPath)
{
$count = 0;

$dir = dir($dirPath);
while ($file = $dir->read())
{
if ( $file == ".." || $file == "." || substr($file,0,1) == "." )
continue;

  $file = $dirPath . "/" . $file; // get the full path

  if (is_file($file)) // a file?
  {
     $count += filesize($file);
  }
  else if (is_dir($file)) // a sub-directory? then recursively scan it
  {
     $count += du($file);
  }

}
$dir->close();

return($count);
}

[Anon]

...sorry about the lack of tabs/spaces, I definitely had
them, the page script must have removed 'em!

About the 'substr()' <-- remove this in the
name check, I needed it for my app so it didn't
check 'hidden' files on the web server. In my app,
a remote file manager, I didn't want to take into
account the hidden files.

• Rod

[Anon]

Great function thanks!

[Anon]

No problem - glad to have helped out!

• Rod

[Anon]

When i use this function, it returns a wrong disk space value... my du returns 17678336 bytes, otherwise your functions returns 19517370 bytes...

why ? thanks.

[Anon]

Thank You!!! This is exactly what I needed!