Print function where it's situated in the PHP code

[Anon]

Yes, is that possible.

I want to print some text depending on the result of a database-query, above the output of the database-query.

I do this now, but it doesn't work:

function TextMessage($myname)
{
if ($myname != '')
{
echo "<h1>Welcome to my homepage</h1>";
}
else
{
echo "<h1>Your are not welcome here!</h1>";
}
}

...mysql_qery this and that...
for each mysql_fetch_array
{
echo "Firstname: $fetch["firstname"]
echo "Lastname: $fetch["lastname"]
}

if ($a_name_was_found)
{
TextMessage($the_found_name)
}
...end mysql_query_stuff ...

I want this to be a possible outcome:

<h1>Welcome to my homepage</h1>

Firstname: John
Lastname: Doe

Is it possible??

[Anon]

Try

$not_welcome_names = array(
"Mother In Law",
"Head Teacher",
"Never Buys the Beers"
);

function TextMessage($myname)

global $not_welcome_names;

if ($myname) {
if(in_array($myname,$not_welcome_names)) { # this relies on php > 3
echo "<h1>Your are not welcome here!</h1>";
}
} else {
echo "<h1>hiya!</h1>";
echo $myname;
}
}

etc.....