What's wrong? And files on the user's computer?

Anon

What's wrong with the following code? I keep getting Parse Error on the line starting with $1Content.

    function thank_you(){

$1Content = ' 
Your form input has been processed. Thank you, '. $Name .' , for your contribution. Please click on a link to further browse our site.';
$1filename = "stuffTemplate.html";
$1fd = fopen($filename, "r");
$1blah = fread($1fd, filesize ($1filename));
fclose ($1fd);
$1convert = str_replace("{CONTENT}", $1Content, $1blah);
$1final = str_replace("{title}", "Thank You for your Feedback.", $1convert);
echo $1final;
}

Also, how do I access files on the user's computer? I keep getting an error saying the file cannot be accessed when the value is C:\whatever\file.txt , the file is there but it cannot access it.

Please help.

Anon

I am not sure what you are trying to do here, but try changing '. $Name .' to $Name and double-quote the string in line 2. Then it appears the the variable in your fopen() function does not match what you defined.

Anon

I cannot double quote the second line as you do not see that there are already double quotes for the .

Also, changing the '. $Name .' to $Name does not help.

Thanks for the variable on the fopen() but the whole thing still does not work.

Thanks for trying to help but the whole thing still does not work.

Anon

Don't start a variable with a number
change $1Content to $Content1 or something like that. That might be the problem

Anon

Thanks for your help!!

THANK YOU SO MUCH!!!

Thank you man!

Thank you!

Thanks!

Bye!