Where's the parse error?

[Anon]

<?php
if($hero->f("Image") != ""))
{
printf("<img src=\"%s\">", $hero->f("Image"));
}
?>

[Anon]

What is $hero? is this your db object?
Also if you use single quotes around your printf statemtn, you don't have to worry about escaping your double quotes like below:
printf('<img src="%s">', $hero->f("Image"));

Also where is the error showing up at?

[Anon]

You have an extra right paren in your if() statement, this would be the fixed line:

if ($hero->f("Image") != "") {
...
}

Yours looks like an if()) statement 😉

--Ryan

Nico wrote:

<?php
if($hero->f("Image") != ""))
{
printf("<img src=\"%s\">", $hero->f("Image"));
}
?>