How to pass an array from 1 function to another?

Anon

I have a script which creates a web page which displays details of members of staff.

I am looking at allowing the users to change the details on this screen.

Most of the details only have 1 value eg. Surname, but there are a couple that have more than 1 value eg. Deparment STP,
Technical Support
32.
and is stored in field ou[0],ou[1] and ou[3] respectfully. The screen only holds the [0] field.

I have overcome the problem of capturing the subsequent values by running a function
(define_oddeleni) which will add the other values to the ou field. The values of the ou array are correct ie. all 3 values appear when I do an echo.

This function is called from within another function (zmenit_data) but only the [0] value is known.

How do I transfer the values of the array from define_oddeleni to zmenit_data.

Here is a snippet of my code:-

function zmenit_data()
{
global $HTTP_GET_VARS;
global $input;
while (list($key, $value) = each (HTTP_GET_VARS))
{
$input = array (
"$key" => array ("0" => "$key: $value",
);

               if (($key) == "ou")
               define_oddeleni(&$value);

               echo "array = ".$input[$key][1]."<br>";

               etc.
               }

function define_oddeleni(&$value)
{
global $HTTP_GET_VARS;
global $input;
if (($value) == "STP")
{
$input = array (
"$key" => array (
"0" => "$key: $value",
"1" => "$key": Technical Support",
"2" =>"$key: 32"
),

               ); 
               }
               }

There are 15 keys for each record.

LDAP requires this information as an array in order to modify its database.

I hope you can help

Thanks in advance

Tony

Anon

Maybe you can use the array_merge() built-in function.

From the PHP Manual:

Example 1. array_merge() example

$array1 = array("color" => "red", 2, 4);
$array2 = array("a", "b", "color" => "green", "shape" => "trapezoid");
array_merge($array1, $array2);

Resulting array will be array("color" => "green", 2, 4, "a", "b", "shape" => "trapezoid").

Anon

1 - In function zmenit_data
You don't need to pass $values by reference to define_oddeleni as it is already done in define_oddeleni. Just call define_oddeleni($values)
( Manual chapter 12 : Functions)

2 - In define_oddeleni
2.1 $key is undefined.
2.2 Avoid using global variables if possible. Use return instead.
eg:
function define_oddeleni(&$values) {
...
$input= array(...);

return $input;
}

and call
function zmenit_data() {
...
$input = define_oddeleni($values);
...
}

2.3 "1" => "$key": Technical Support",  <= You've put 1 " after $key this should cause a parse error.

Hope this may help

JBL