ereg help

Hello,
can anyone help me with ereg
I need to return what is between the @'s in the following sample line.

0 @I9L34-NT@ INDI

the first number in the line has to be 0

I want to return what is between the @'s

the word INDI has to follow the @'s

thanks for any help

Mitchell Young

while (ereg('0 @[A-Z0-9-]@ INDI', $string, $array)) {

$result .= substr($array[0], 3, -6);
}

echo $result;

havent tested it, but it will return all the mathching result between @'s in $result.

ok, i just tested this one, and it works 🙂
sorry, just ignore the last post..

//if the source is $string, then:
$string = "0 @I9L34-NT@ INDI 0 @I77L34-NT@ INDI";

while (ereg('0 @[A-Z0-9]{1,}-[A-Z]{1,}@ INDI', $string, $array)) {
$result .= substr($array[0], 3, -6);

$string = ereg_replace($array[0], '', $string);
}

echo $result;
exit();

Thanks, Daarius
you got me on the right track.
the following does what I wanted.

if(ereg('0 @([a-zA-Z0-9]{1,}-[a-zA-Z0-9]{1,})@ INDI', $line, $result))

{
print("$result[1] <BR>");
}