Return optionally two variables from function

[Anon]

I want to turn this into a function:

$PROSPECT = "found"; // set by default
$prospect_product == something from a form.

// begin crucial testing //
if ($prospect_product == "hello")
{
$product = "A hello product";
}
else
{
$product = "a realy bad product";
$PROSPECT = "not found"; // change your mind about $PROSPECT
}
// end crucial testing //

As you can see the // crucial testing // uses only one variable, but is the testing inside it, it needs to change another variable.
I know that if I make the crucial testing a function I can reach $PROSPECT by Global'ing it.
But if I need to Global it back outside the function, how do I do then?
How do I return two values from a function?
Make them one variable? Make them an array?

Grateful!

[Anon]

why not just return 0; if it's not a hello product.. And if it is a hello product return "A hello product".. I hope this will solve your needs...

Andreas Bernhardsen

[Anon]

If you want to change GLOBAL variables, read then manual about functions:

Making arguments be passed by reference

By default, function arguments are passed by value (so that if you change the value of the argument within the function, it does not get changed outside of the
function). If you wish to allow a function to modify its arguments, you must pass them by reference.

If you want an argument to a function to always be passed by reference, you can prepend an ampersand (&) to the argument name in the function definition.

function add_some_extra(&$string) {
$string .= 'and something extra.';
}
$str = 'This is a string, ';
add_some_extra($str);
echo $str; // outputs 'This is a string, and something extra.'

[Anon]

thank you very much.

Learning-as-you-get-along, can be hazardous sometimes.

[Anon]

That's why we have a soft and fluffy manual to hold on to. :-)