if value equals null print please help!

[Anon]

I'm sure this is an easy one, but I've looked though the MySQL manual and PHP Manual and can't find the answer.

Thanks
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if ($firstname = NULL) {

printf ("<center><font color=\"red\"><b>Please complete your First Name</b></font></center>");

} elseif ($lastname = NULL) {

printf ("<center><font color=\"red\"><b>Please complete your Last Name</b></font></center>");

[Anon]

try...

if ($firstname == NULL) {

...notice the double equal sign used for comparison; single equal sign for assignment.

-- Rich Rijnders
-- Irvine, CA US

[Anon]

Thanks Richard,

It still will not work. Is there something else?

Thanks, Stuart
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if ($firstname == NULL) {

printf ("Please complete your First Name");

} elseif ($lastname == NULL) {

printf ("Please complete your Last Name");

[Anon]

Well, the other thing you should consider is if NULL is really what you want to be comparing your variable to. NULL and "blank" are not the same thing.

It looks like you variable may be the result of, perhapse, a form field. If that is the case, then you should compare it to "" (blank) or, better yet, "empty"; not NULL:

if (empty($firstname)") {

-- Rich Rijnders
-- Irvine, CA US

[Anon]

I read something somewhere that you cannot use = comparison characters when dealing with Null. You have to use "IS NULL" and "IS NOT NULL"