having eval() outputting the result to a variable?

Anon

Does anybody now if it is possible to have the eval() function output it\'s result
to a variable or a file?

Anon

from the manual;

A return statement will terminate the evaluation of the string immediatley. In
PHP4 you may use return to return a value that will become the result of the
eval() function while in PHP3 eval() was of type void and did never return
anything.

--
rad

skyxmen

i have an array of SQL query , for example
$result[0] = "mysql_db_query(\"$dbname\",$reqtype0)";

how do i use eval function to make php executes $result[0]

i have tried
$aresult = eval ("\$result[$0];");
then
while ($row = mysql_fetch_array($aresult))
{
...
}

i have also tried
eval("\$aresult = \"$result([0]\";")

but it keep saying Warning: Supplied argument is not a valid MySQL result
resource

is there something wrong with my code..
any suggestion how to execute codes in database textfield for later execution ...

Anon

Hi,
Your problem is not related to eval(). It is obviously working well beacuse the error msg you get comes from MySQL. Now, this error msg is typically produced by performing a query while not connected to the DB. Check your DB connection is working. Try also using mysql_error() to get more info about the erro.
Good luck.

Anon

You have to buffer the eval output if you want to capture it to save to a file:

<CODE>
// $template is a mixture of html and php variables that need to be eval'ed

$html = join (" ",file ($template));
ob_start();
eval ( "?>" . $html . "<?");
$output = ob_get_contents ();
ob_end_clean();

</CODE>

Now the variable $output can be written to a file!!

Cheers!