$ and if

[Anon]

I want the result to be a string with $rvar1: $rvar1d, $rvar2: $rvar2d
I used the != to see if $rvar1 is not empty.
What I want is a working piece of the code.
Would someone help out.

Regards Spencer

$result=
if ($rvar1 != "") {"$rvar1: $rvar1d, ";
}
if ($rvar2 != "") {"$rvar2: $rvar2d";
}

[Anon]

You can shortcut your if evaluation as follows (and here's the code you want)...

if($rvar1) $result = "$rvar1: $rvar1d, ";
if($rvar2) $result = "$rvar2: $rvar2d";

[Anon]

Turn it around:

if ($rvar1 != "") {
$result = "$rvar1: $rvar1d, ";
} elseif ($rvar2 != "") {
$result = "$rvar2: $rvar2d";
}

and so on...

This should work depending on what your desired outcome is.

Jim

[Anon]

Actually I think Kyle is more on track with this one but I think Spencer wants to concatenate the two strings and make one string called $result
Use this:
if($rvar1) $result .= "$rvar1: $rvar1d, ";
if($rvar2) $result .= "$rvar2: $rvar2d";

[Anon]

After I submitted this one and then saw Kyle's response, thats what dawned on me as well.

Jim

[Anon]

Thanx, I will test the code on monday.

Spencer

[Anon]

It worked, the only problem I found that if the database was empty it would keep the old values of rvar1 etc.
I fixed this by putting an extra line to it:
$result="";

Is it normal that if the database field is empty it will keep its old value?

Regards
Spencer