nested if/else statements in loop

[Anon]

He everyone! I am learning PHP and am new to coding in general - maybe PHP wasn't the best to start with, but I did 🙂

What I am trying to do is detect a variable out of a db and if it's one thing make the text bold, but if it's another it is normal. I am not having much luck with it, though. The if/else statement is logical enough to me, but apparently not to PHP because it apparently completely ignores it. Is there a problem with having an if/else statement inside the loop? Is there a better way to accomplish what I'm trying to do?

Any assistance would be awesome - thanks in advance!
- Michael

if ($myrow = mysql_fetch_array($result)) {

echo "<table width=780 border=0 cellspacing=5 align=center>\n";

do {
// display results in table //
printf("<tr>");
printf("<td width=77 align=center valign=middle>");
printf("<a href=\"%s\"><img src=%s border=0></a>\n", $myrow["link"], $myrow["thumbnail"]);
printf("</td><td width=68 align=center valign=middle>");
// detect if basic or premier, make bold if premier //
if ($myrow["bas_prem"]='premier') {
print "<b>";
} else {
print "";
}

printf("<font size=2><a href=\"%s\"><font color=#0000CC>%s</font></a></font>\n", $myrow["link"], $myrow["lstg_num"]);

if ($myrow["bas_prem"]='premier') {
print "</b>";
} else {
print "";
}

printf("</td><td width=135 valign=middle>");

if ($myrow["bas_prem"]='premier') {
print "<b>";
} else {
print "";
}

printf("<font size=2>%s<br>%s<br><font color=#FF0066><b>%s</b></font></font>\n", $myrow["address"], $myrow["area"], $myrow["open_house"]);

if ($myrow["bas_prem"]='premier') {
print "</b>";
} else {
print "";
}

printf("</td><td width=200 valign=middle>");

if ($myrow["bas_prem"]='premier') {
print "<b>";
} else {
print "";
}

printf("<font size=2>%s<br><font color=#FF0066><b>%s</b></font></font>\n", $myrow["description"], $myrow["descr_note"]);

if ($myrow["bas_prem"]='premier') {
print "</b>";
} else {
print "";
}

printf("</td><td width=70 align=center valign=middle>");

if ($myrow["bas_prem"]='premier') {
print "<b>";
} else {
print "";
}

printf("<font size=2>%s</font>\n", $myrow["bedrooms"]);

if ($myrow["bas_prem"]='premier') {
print "</b>";
} else {
print "";
}

printf("</td><td width=70 align=center valign=middle>");

if ($myrow["bas_prem"]='premier') {
print "<b>";
} else {
print "";
}

printf("<font size=2>%s</font>\n", $myrow["bathrooms"]);

if ($myrow["bas_prem"]='premier') {
print "</b>";
} else {
print "";
}

printf("</td><td width=99 align=right valign=middle>");

if ($myrow["bas_prem"]='premier') {
print "<b>";
} else {
print "";
}

printf("<font size=2>$%s<br><b><font color=#FF0066><b>%s</b></font></font>\n", $myrow["price"], $myrow["price_note"]);

if ($myrow["bas_prem"]='premier') {
print "</b>";
} else {
print "";
}

printf("</td></tr><tr><td height=2 colspan=7 bgcolor=#0000CC></td></tr>\n");

} while ($myrow = mysql_fetch_array($result));

[Anon]

Well, the bold tags are not showing up in the code I just posted - but where the text gets bold and then stops is where the bold tags are.

Thanks!

[Anon]

Well, maybe my post was a little premature 🙂

I played around a little more and found that my problem with the ignored if/else statement was solved using the following:

switch ($myrow["bas_prem"]) {
case premier:
print '<b>';
break;
case basic:
print '';
break;
}

<b>as a replacement for</b>
if ($myrow["bas_prem"]='premier') {
print '<b>';
} else {
print '';
}

Thanks for all your help - even if it wasn't in reply to this question. This is a great resource!

[Anon]

Your problem is that you are not testing for the right thing.

This:

if ($myrow["bas_prem"]='premier')

is testing to see if you can put 'premier' into $myrow["bas_prem"].

If you want to test equality, use a double =

if ($myrow["bas_prem"]=='premier')

Read the manual about control structures