including php tag inside html tag

Anon

Hi,
In my database, I have a table with three fields: uid, name, url. I also have a link in my html page looking like this:

<a href="link.php?uid=<?php echo $row["uid"]; ?>">click here</a>

I wanted it to produce a link with the uid included, but it appears that the uid isn't included. All I got from the produced html is
<a href="link.php?uid=>click here</a>

Can anyone tell my what might be wrong with it? I am sure the information is retrieved from the database with mysql_fetch_array.

Anon

the code looks ok - are you SURE the uid id being returned?

Just add a line above the href line something like:
<?php echo 'The uid id: ' . $row["uid"]; ?>

to make sure. If not, which I suspect is the case, then post your db lookup code and we can see what might be the issue.

Hope this helps

Darren

Anon

Text you print from variables is not parsed.

if you want to process the php commands in the string, you need to use the eval() function.

Anon

Vincent could you elaborate, I use code like his everyday and it works fine!

Anon

you can do this:

$value="a lot";
print "Hello, my value is $value";

outputs: Hello, my value is a lot.

but you can't use this:

$value = "<? echo 'hello' ?>";
print "Hello, my value is $value";

because it outputs:
Hello, my value is <? echo 'hello' ?>

So, if you have PHP tags in the content of your database fields,
and you print the content of those fields, you print the php tags, not the outcome
of those tags.