How to run a function from a link?

Anon

I've added user logins to my intranet but am trying to figure out how to allow them to logout from a link on the main page. I want them to click on a link called 'LogOut'. When this happens, I want the page to refresh and show that nobody is logged in.

I created the following function and put it in my functions.php file:
// Logout of Intranet
function Logout($user_name) {
session_unregister('user_name');
}

The index page has the following code in it:
session_start();
$session_name = session_id('user_name');

if ($user_name) {
$sql = "SELECT first FROM employees WHERE user_name = '$user_name'";
$result = db_query($sql);
$myrow = db_fetch_array($result);
$first = $myrow['first'];
echo "<TD align='left'>Welcome back, $first!</TD>
<TD align='right'><a href='index.php'>Logout</A></TD>\n";
} else {
echo "<TD align='left'>You are not logged in yet.</TD>
<TD align='right'><a href='account/login.php'>Login</A></TD>\n";
}

Anyone have any ideas?

Anon

The simplest way I gues would be to have your functin within an if statement that is activated by a variable in the url.

if($logout)
{
function goes here
}
else
{
other stuff
}

then at the bottom of your other script have the url for logging out like this:

<a href='index.php3?logout=true'>Logout</a>

rgds,
scott d~

Anon

Why don't you make a separate page called logout.php to log the user out and then redirect back to the index page.(This is exactly what I did for my Intranet)

<?php
/
Filename - logout.php
Destroys user session and redirects
/
session_start();
session_destroy();
Header('Location: http://my.intra.net');
?>

Anon

Thanks, that did the trick.