displaying images

[Anon]

I want to display some images in a table.
This first bit of script displays the file names that I have saved in a table.
It works!

<?
print ("<table>\n")
while ($row = mysql_fetch_array($result)){
$IMAGE = $row["image"];
echo"
<tr>
<td>$IMAGE</td>
</tr>
";
}
print ("</table>\n")
?>

So why do I get Parse error using this script.

<?
print ("<table>\n")
while ($row = mysql_fetch_array($result)){
$IMAGE = $row["image"];
echo"
<tr>
<td><img src="$IMAGE.gif"></td>
</tr>
";
}
print ("</table>\n")
?>

A solution would make me very happy.

[Anon]

The quotations around the img src="$IMAGE.gif" are going to screw it up, because if you notice, that is what is surrounding the entire echo statement, and the parser is looking for to end the string. Simply escape these quotation marks (to escape a character, it means to add a backslash ( \ ))

<?
print ("<table>\n");
while ($row = mysql_fetch_array($result)){
$IMAGE = $row["image"];
echo"
<tr>
<td><img src=\"$IMAGE.gif\"></td>
</tr>
";
}
print ("</table>\n");
?>

Hope that helps!

Chris King