ereg and string help

[Anon]

I am using the following code to pull some variables out of a string.

$query_string = ereg("p=(.*)&", "http://google.yahoo.com/bin/query?p=waxpack&hc=0&hs=0", $search_term);

echo "$search_term[1] <br>";

I am trying to pull the information between "p=" and the first "&", but I get a return of: waxpack&hc=0

Can anyone help me to get a return of just the word "waxpack"?

Thanks in advance.

Jared

[Anon]

Whatchew getting back?

How about:

$str = "http://google.yahoo.com/bin/query?p=waxpack&hc=0&hs=0";
$qry = ereg("p=([^&]*)", $str, $st);
echo $st[1];

???

adam

[Anon]

Thank You :-)

Got another question ...
If I have a string of:
?p=%27waxpack&hc=0&hs=0

How do I search for the % sign, and delete that along with whatever 2 numbers are afer it, completely out?

Thanks in advance. :-)

Jared

[Anon]

$newstring = preg_replace("/%\d\d/","",$string);

will replace all the %\d\d in the string. if you want to confine it to the one just after the "=" do

$newstring = preg_replace("/=%\d\d/","=",$string);

--
rad