Parse error outside PHP code !

Anon

Hello...

...I'm facing a dificult problem. The PHP parse reports that there is a parse error on the last line of my page, wich is a PHP + HTML. But therefered line is the line after .
I've checked the code, nothing ! Everything looks fine, but the parse error is there. Does anyone has any clue please ? Can I have nested "if"s in my code ? That's it !

Thank you...

and by the way, PHP + MySQL rlz !!

Anon

cant say anything untill i can see the code. if its possible do paste the final part of the code.

Anon

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Anon

sdfsdfsdf

Anon

Anderson,

It sounds like you've left out a } in one of your if statements, or left out a ; in one of your calls to a function. Just taking a guess, but it would be easier if you pasted your code here.

[ John Barker
[ Resident PHP Hacker(TM)

Anon

So, the code is a little big since i nested some functions in one simple page, but here it its the main of my code, i dont think theres any parse error. Maybe I need to send you the hole file, cos there´s more PHP code on it. Everything was working fine before I add the / Edit Entries / part. I´ve declared a hidden HTML object named "hidden" to be my control in chosing /Add/ or /Edit/ when the form is posted to this same page. If you need the hole code i can send to your email or leave it here wherever I´ll be able to, since i think that this Phorum can´t print HTML tags.

<?php

$usr="anderson";
$pwd="password";
$host="localhost";
$db = "adhonep";

$link = mysql_connect($host, $usr, $pwd);
if (!$link) { echo ("Erro: " . mysql_error() . " \n"); }

/ Delete Entries /

if ($task=="del") {

$SQL = " DELETE FROM $table ";
$SQL = $SQL . " WHERE id = $id ";
$delete = mysql_db_query ($db, $SQL, $link);
if (!$delete) { $status = "Erro: " . mysql_error() . " \n"; }
}

/ Show Editable Entries /

if ($task=="edit") {

$hidden="Atualizar";
$SQL = " SELECT * FROM $table ";
$SQL = $SQL . " WHERE id=$id ";

$result = mysql_db_query ($db, $SQL, $link);

$data = mysql_fetch_array($resulf);

$nome = $data["nome"];
$atividade = $data["atividade"];
$telefone = $data["telefone"];
$resumo = $data["resumo"];
}

if ($REQUEST_METHOD=="POST") {

/ Edit Entries /

if ($hidden = "Atualizar") {
if ($nome == NULL) {
$status = "Por favor coloque um nome.";
}
elseif ($atividade == NULL) {
$status = "Você deve informar uma atividade.";
}
elseif ($telefone == NULL) {
$status = "Informe um número de telefone.";
}
elseif ($resumo == NULL) {
$status = "Digite um resumo de testemunho.";
}
else {

$SQL = " UPDATE $table SET";
$SQL = $SQL . " nome = '$nome', ";
$SQL = $SQL . " atividade = '$atividade', ";
$SQL = $SQL . " telefone = '$telefone', ";
$SQL = $SQL . " resumo = '$resumo' ";
$SQL = $SQL . " WHERE id = $id ";

$update = mysql_db_query ($db, $SQL, $link);
if (!$update) { $status = "Erro: " . mysql_error() . " \n"; }

$status = "Adhonepiano Atualizado !";

$nome = NULL;
$atividade = NULL;
$telefone = NULL;
$resumo = NULL;
}
}

/ Add Entries /

else {

if ($nome == NULL) {
$status = "Por favor coloque um nome.";
}
elseif ($atividade == NULL) {
$status = "Você deve informar uma atividade.";
}
elseif ($telefone == NULL) {
$status = "Informe um número de telefone.";
}
elseif ($resumo == NULL) {
$status = "Digite um resumo de testemunho.";
}
else {
$SQL = " INSERT INTO $table (nome, atividade, telefone, resumo) ";
$SQL = $SQL . " VALUES ('$nome','$atividade','$telefone','$resumo') ";

$insert = mysql_db_query ($db, $SQL, $link);
if (!$insert) { $status = "Erro: " . mysql_error() . " \n"; }

$status = "Adhonepiano Adicionado !";

$nome = NULL;
$atividade = NULL;
$telefone = NULL;
$resumo = NULL;
}
}