too few arguments

Anon

Warning: printf(): too few arguments

I'm trying to get results back from the MySQL database with some text that is written in french But I get this error, anyone know how to fix it? The text looks the same in the database.

For example:
être rémunéré en surfant

Anon

Please send your code

Anon

$ekeywords = urlencode($keywords);
$dkeywords = urldecode($ekeywords);

$result=mysql_query("select keywords from keywords where keywords like '%$dkeywords%' limit 0,10",$db);

if ($myrow = mysql_fetch_array($result)){
printf ("Similar Keywords");

do {

$keywordsuggestion=($myrow[keywords]);
$ekeywordsuggestion = urlencode($keywordsuggestion);
printf(" <a href=\"search.php3?keywords=$ekeywordsuggestion\">$keywordsuggestion</a>");}

while ($myrow = mysql_fetch_array($result));

}else {}

printf ("

Anon

You shouldn't be using printf() here in the first place! printf()
is needed when you have specific formatting requirements for
a particular variable (e.g. display an integer with leading zeros)
but you don't seem to be doing that here.

As far as the error itself, my guess is that one of the variables
you're inserting contains a %s or %d sequence which would
lead printf() to look for additional arguments to insert, but
there are none.

Anon

Thanks, that did the job!