getting extentions from filesnames

[Anon]

I am using the following to get the extenstion from a filename
filename.ext

ereg(".(.+)$", $filename, $ext);

will return "ext"

however

file.name.ext
will return "name.ext"

how do I improve on the regex to get just "ext"?

thanks

[Anon]

What I did was use the substr function. It looks like this:

$handle=opendir($sPath);
while ($filename = readdir($handle)) {
if(substr($filename,-4) == "$ext"){
echo $filename;
}
}

This will print out all files with the extensions that you specify. One thing you need to know, the negative four onle takes the last four characters of a filename and looks at them. In onther words, if you have a file with a .command extension, it will only look at the mand. Hope this helps!

[Anon]

You need to make the matched part be any character
except a dot:

  ereg( '.([^./]+)$', $filename, $ext);

[Anon]

Oops, the regex above is correct, but I didn't
describe it quite correctly. It matches the
last dot followed by a sequence of non-dot-non-
slash characters, and stores the sequence (but
not the dot) into $ext[1].

In other words, $filename can be a full or partial
pathname with as many slashes or dots as it
wants, and you're guaranteed to get what
follows the last dot in the last name component
(if any).

[Anon]

great thanks
that is was I was looking for.