Parse error: parse error in script

[Anon]

I think i\\'m missing something here. when i run my php script, i get a error with this part of it:

The error message is :

Parse error: parse error, expecting `\\')\\'\\' in nick.php on line 32
The line 32 is:
while($srow = mysql_fetch_array($comment))

---

the code i have is:

print \\"name: $srow[name]<br>\\";

$SUBMITDATA = Array (

while($srow = mysql_fetch_array($comment)) 
{
		\\\"$srow[name]\\\" => Array (
		\\\"where\\\" => \\\"$srow[name]\\\",
		\\\"wzone\\\" => \\\"$srow[wzone]\\\",
		\\\"method\\\" => \\\"$srow[method]\\\",
		\\\"url\\\" => \\\"$srow[url]\\\",
		\\\"success\\\" => \\\"$srow[success]\\\",
		\\\"failure\\\" => \\\"$srow[failure]\\\"
),

}

[Anon]

First off, I am assuming that $comment is the result set of a "mysql_querry()" function? If so, how can you print $srow[name] when you don't assign it a value until 4 lines later with the "$srow=mysql_fetch_array($comment)" assignment?

Second, it appears that you are trying to create a two dimentional array called $SUBMITDATA (?) with a row corresponding to each record returned from the querry (?)

If this is the case (and even if it isn't) you can't have a WHILE loop inside an ARRAY condtructor. You should rearrange your code to something more along these lines:

$SUBMITDATA[] = "";

while($srow = mysql_fetch_array($comment)) {

print "name: $srow[name]<br>";

$SUBMITDATA[$srow['name']]['where'] = $srow['where'];
$SUBMITDATA[$srow['name']]['wzone'] = $srow['wzone'];
$SUBMITDATA[$srow['name']]['method'] = $srow['method'];
$SUBMITDATA[$srow['name']]['url'] = $srow['url'];
$SUBMITDATA[$srow['name']]['success'] = $srow['success'];
$SUBMITDATA[$srow['name']]['failure'] = $srow['failure'];

}

That should do the trick.

-- Rich Rijnders
-- Irvine, CA U.S.

[Anon]

Thank you Richard, that helped a lot!
E-Mail me [e-mail].

Thanks!
nick