PHP in table (eval doesn't work)

[Anon]

I've sprinkled some php into an html form that I store in a MySQL table. I pull the table date into a php page using print($form);

For forms that only have html in them, this works fine (the correct information is printed to screen).

However, for the form that has php sprinkled in, I get the php printed to screen if it were text.

I've tried eval($form);

but that returns 'Parse error: parse error in Eval code on line 1' for both the php-sprinkled AND the html forms.

Any suggestions on storing php code in a table? and how I would go about printing (and running) the code?

[Anon]

Try eval("?> $foo <?"); where $foo contains your html.

[Anon]

That worked.

The "?>" I had in my eval statement

eval("?>" $foo);

wasn't working (that's what I get for copying from a book).

I didn't think about opening the <? again inside the eval.

Thanks again!