PHP Warning on $submit

[Anon]

I am getting a warning like this when my .php page loads:

"Warning: Undefined variable: submit in C:/XITAMI/webpages/test2.php on line 12"

The code I am using is:

---

<?php

if ($submit) {

// process form

$db = mysql_connect("localhost", "root");

mysql_select_db("test",$db);

$sql = "INSERT INTO shop2 (Name,Address,Phone) VALUES ('$name','$address','$phone')";

$result = mysql_query($sql);

echo "Thank you! Information entered.\n";

} else{

// display form

?>

<form method="post" action="<?php echo $PHP_SELF?>">

Name:<input type="Text" name="name"><br>

Address:<input type="Text" name="address"><br>

Phone:<input type="Text" name="phone"><br>

<input type="submit" name="submit" value="Enter information">

</form>

<?php

} // end if

?>

---

I am new to PHP and I don't really know why I get this warning message. The info I enter in the database works fine however.

I use the latest PHP version, MySql and Xitami Web Server.

Can anyone help?

Thanks,

Robert

[Anon]

Well im a bit confused on why you do not have your password in the mysql_connect?

Also for your if statment you can use isset()
But will do the same thing as what you have.

[Anon]

What do you expect to be the value of a submit button ??? As far as I know the button only calls the script defined in Action... but doesn't hold any value (and exactly that says your error message)

cya Rob

[Anon]

The form variable, $submit, isn't created until someone hits the submit button. So when your page first loads, the if statement is trying to evaluate a non-existent variable. Derek's suggestion, using if(isset($submit)) instead of if($submit), should take care of this for you.