Loops that doesn't exit... it seems...

[Anon]

Until this piece of code was inside a Switch control it was working, as I put it in a IF statement it always returns me an error, see at the end of the message:

---

if ($numeropezzi >= 2) {

echo ("Numeropezzi >= ".$numeropezzi);
$j=0;
while (isset($pezzoattore[$j])) {
	$whereattore=$whereattore."(attore1n LIKE '%".$pezzoattore[$j]."%' OR attore1c LIKE '%".$pezzoattore[$j]."%'
	      OR
	      attore2n LIKE '%".$pezzoattore[$j]."%' OR attore2c LIKE '%".$pezzoattore[$j]."%'
	      OR
  		      attore3n LIKE '%".$pezzoattore[$j]."%' OR attore3c LIKE '%".$pezzoattore[$j]."%')";
	if (isset($pezzoattore[$j+1])) {
		$whereattore=$whereattore." AND ";
	}
	$j++;
}
echo $whereattore;
    break;

}

---

Fatal error: Cannot break from 1 loop(s) from nesting level 0 in /home/httpd/html/chivideo/cube.php3 on line 161

I really don't understand why :-(
It seems ok ...

[Anon]

OK OK !!

I understand why... sorry to bother you...It's 6 ours now that my mind doesn't take a break !

It was just the "Break" statement I forget from Switch the cause of the trouble...

But... is out there any program to check syntax while coding ?

I'm using notepad but it is really not the best way to do it...

How do you compile PHP code usually ?

Thank you

[Anon]

You can not BREAK out of an IF condition. Just remove the BREAK or use RETURN if you want to end the function.

-- Rich Rijnders
-- Irvine CA US

[Anon]

I tried UltraEdit on the suggestion of people in this group and I like it. It wouldn't have found your BREAK problem, though.

-- Rich