how do I read the 2nd variable in a query string?

Anon

I want to pass the id of a row and the name of the table it came from between two pages.
If I have a link that says:

<a href=\"alter.php3?".$row["id"]."&".$table."\">alter</a>

how do I call the second variable ($table)?

The first one I can call simply by saying:

echo $id;
or
echo argv[0];

but saying:

echo $table;
or
echo argv[1];

produces no results at all...
am I phrasing the original link properly?
any suggestions would be most welcome :o)

thanks - dunstan orchard

Anon

May be, I'm too new to PHP to know some details, but I would write it this way:

<a href=\"alter.php3?row=".$row["id"]."&table=".$table."\">alter</a>

It always works, and you see $row and $table variables in your script. Hope, it's what you need :-)

Anon

Unless you really have a burning desire to do things in a nonstandard way, you should rewrite the code that generates your link. The Web convention is to pass arguments in name=value&name2=value2 format, which PHP automatically decodes into $name and $name2.

Anon

Hooray!

seems to work now... I can read both values off on a test page :o)

thanks - dunstan