Include.. if statements.

[Anon]

Hi,
I'm not sure if this is possible or not.

Can I include/require a file that leaves an open if statement, so on a main page i have

include("openif.php");
include("dothis.php");
include("closeif.php");

I have tried something along those lines with
<?
if (something==somethingelse)
{
?>
in the openif file but it returns errors on line 5?
are there any other ways to do this?
any ideas would be appreciated.

Regards
- Adam

[Anon]

Hi Adam,

as long as you keep the brackets clean, I can't think of a reason, why it shouln't work.

cya Rob

[Anon]

I dont understand what you mean by "clean" brackets.

Code Snippets:
//openif.inc

<?php
if($answer=="y") {
?>

//dothis.php
<?php
echo "Correct";
?>

//closeif.inc
<?php
}
else
{
echo "wrong";
}
?>

//all.php
<?php
$answer = "y";
include("openif.php");
include("dothis.php");
include("closeif.php");
?>

when running all.php
it returns

Parse error: parse error in /web/sites/315/pizzaboy/www.pizzaboy.f2s.com/openif.php on line 3
Correct
Parse error: parse error in /web/sites/315/pizzaboy/www.pizzaboy.f2s.com/closeif.php on line 2

[Anon]

with the "clean" brackets I ment, that you don't forget to close the if-brackets or similar, but you didn't ... Anyway I tried it now for my own... And it doesn't work ... Haven't thought that... But what works ... I hope it is similar enough to what you need ...

(if.php)
<?php

if ($var == 5)
{
include ("./action.php4");
}
?>
(action.php)
<?php

echo $var;

?>
and in your all.php you use:
<?php

$var = 5;

include ("./if.php4");

?>

cya Rob