Opening gif based on a condition

Anon

I am extremely new to PHP and am stuck on setting up a flag for checking to see if a file exists. We have a folder of pics who's names link with the employee id's in the database. The web page is supposed to show the pic for each person as they're picked. However if there is no pic, i want to have text("will be here soon") to be put in it's place. How do i set up an If statement to check to see if the file exists ... hope this makes sense!

thanks in advance

Anon

How about something like:

if (!(is_file($filename)){
print "Will Be Here Soon";
}
else{
Do display here
}

Does that help?

Anon

ACtually, i'm trying to do this in Homesite, so right now i have this code with the rest of the code

echo "<td colspan=2 bgcolor=\"#FFFFFF\"><font face=\"Verdana, Arial, Helvetica, sans-serif\" size=\"1\"><img src=\"gif/" . $row["id"] .".jpg\"> </font></td>";

would you know how to set up the if statement around it so that if the image source doesn't exist, then set up a message or another image? I'm used to using Coldfusion, and all the extras that come with it, so i'm having a few problems figuring it out

Anon

Not exactly sure what you're looking for...
Maybe this will help:

$filename=("gif"."$row[id]".".jpg");
if (!(is_file($filename))){
$output="Will Be Here Soon";
}
else {
$output="<img src=\"$filename\">";
}
print "<td colspan=2 bgcolor=\"#FFFFFF\">$output</td>";

Be careful with $row[id], it will need to be an established variable for this to work. You might want to look at another way of generating the file name to the sake of clarity.

Hope this helps.

Anon

Actually, you were right... i had to set a variable equal to the filename, and if it existed then do the stuff.. a lot of it was positioning and doing the setting... so it finally works.. thanks for the help.. i'm glad i was able to find this site!!

Anon

This should do it in one line

echo (file_exists($filename))?("<td colspan=2 bgcolor=\"#FFFFFF\"><img src=\"gif/" . $row["id"] .".jpg\"> </td>")🙁"will be here soon");

In ONE line !

Neville

Anon

WoW! That's less code than i had done.. thanks much!