Sending parameter to PHP generated image

[Anon]

I have a index.php3 page which has a php script in it that outputs a gif image.
This image needs a parameter to work.

the following works :
<img src="pic.php3?Stat=83">

but the following doesn't work :
<img src="pic.php3?Stat=$Stat">

where $Stat would come from a url such as
http://www.mydomain.com/index.php3?Stat=83

is it because the $Stat part of
<img src="pic.php3?Stat=$Stat">
is within quotation marks?

How can I get it to work with parameters entered from the URL

thanx

[Anon]

It'll work just fine if you actually pass the value in the url. From HTML, you need to escape into PHP mode and echo the variable:

<img src="pic.php3?Stat=<? echo $Stat ?>">

This assumes that pic.php3 knows what to do with the argument and knows how to set the mime type correctly.

[Anon]

Hmm...

it still seems as if the image receives nothing.

I have a php generated table right under the php generated image and the table recieves the parameter fine.

And if I go directly to the image through the URL with the parameter, it also works fine.

Its only when the image is within the index.php3 page that it doesn't work.

Steve Yelvington wrote:

It'll work just fine if you actually pass the value in the url. From HTML, you need to escape into PHP mode and echo the variable:

<img src="pic.php3?Stat=<? echo $Stat ?>">

This assumes that pic.php3 knows what to do with the argument and knows how to set the mime type correctly.

[Anon]

Actually, its okay...i got it working