php help!

Anon

I want to be able to read a certain line in the file and also a particular section.

I want to be able to jump to line 3, and be able to take the URL out of the file and print it out on the page.

So if the user decides to go to url.php?id=3 he will get http://www.link3.com

Anon

You can read the files into an array:

/***********************
$fp = fopen($file,"r");
flock($fp,1);

$counter=0;
while(! feof($fp))
{
$line[$counter++]=fgets($fp,1024);
}

flock($fp,1);
fclose($fp);
/***********************

Now all the lines from your file are added into an array.
print"$line[2]"; prints http://link3.com

an array starts counting with 0

I hope this helpes you..
Mark

Anon

actually that prints out 2|http://www.link2.com

Anon

so just remove the x| from the begining of each entry. The line number will identify each link.

Anon

i need the number before the |link

so how would i do it with that then?

Anon

There are lots of different ways of doing this. Here is a simple function to do what you describe.

function printurl($urlnumber, $datafilename)
{
$buf = file($datafilename);
$url = explode('|',$buf[$urlnumber]);
echo $url[1];
}

// usage example

printurl(4,'somefile.txt');

Anon

To print out your entire list from your file, use this:

$file = file("file.txt");
for($count=0;$count<count($file);$count++)
{
$part = explode("|",$file[$count]);
echo $part[0] . ". <a href=\"" . $part[1] . "\">" . $part[1] . "</a>";
}

Similar to what Steve said.

Put your own filename in of course...

---John Holmes...