How to do this?

Anon

Hi, how do you display an image in php without defining a mime type when used in <img src=".php?id=34"> kind of stuff? I want the script to add one to the view (pretty easy with mysql) and then display the image. (the image location should be enough to display the image..) for a banner tracking script

Lets say, would the header(locati..) redirecting work? eventhough the script is called as image source?

Many thanks for replies 🙂

Anon

It is not clear what you're trying to do.

If you are storing image data in MySQL and wish to serve it, then you should write a separate image script that starts out by calling the function header("Content-type: image/gif") or header("Content-type: image/jpeg") to set its mime type.

In that case, the banner rotator script would generate a tag like this:

img src="/path/to/imagescript.php?id=somevalue"

Ordinarily, though, a banner rotator would not store image data in the database, but rather store metadata only and leave the ad banners in the filesystem.

In that case the banner script would generate a normal reference like this, pulling the filename from the database:

img src="/path/to/banner.jpg"

Anon

Every image must have a mimetype setting, or your browser will not know how to handle it.
Webservers set the mimetype automatically, in PHP you'll have to do it manually.

The rest of your question is completely unclear to me.

Anon

Thanks, that is what I exactly was looking for.
Do I have to send headers before executing any other statement?

Anon

You have to send headers before sending any other data. Not necessarily before executing any other statements. For example, you might connect with the db, execute the query, pull in the data, et cetera, before calling header(). But you have to be careful not to send any data -- even a blank space, which will cause PHP to error out.