fsocketopen problem

[Anon]

I want to check if a site is online, using the next lines of code:

$fp=fsockopen("www.phpbuilder.com", 80, &$errno, &$errdesc);

if($fp) {
print"ONLINE" }
else {
print"OFFLINE" }

The error i get is: "Connection timed out" BUT when i use "localhost" instead of "www.phpbuilder.com" everthing works fine!!??

Can anyone help me?
Thanks,
Mark

[Anon]

Have you tried adding the timeout parameter to the fsockopen()?

[Anon]

You must be having some kind of routing or DNS problem.
But also, this code isn't what you are actually running, as
the missing semicolons at the end of the echo lines should
be causing you a syntax error.

[Anon]

Are you behind a firewall , that could also be the problem. Then you have to connect though the proxy server.