search for files

[amelhedi]

I would like to know if php can seach for files .eg(*.mp3) like the windows fonction (F3)
And return the result to a file.

Plz propose a code if possible.

[watski]

Hi,

I prefer to use a shell command for this. Run the find-command and grep for .mp3 and use PHP to collect the output.

$cmd = "find * | grep .mp3"
$fp = popen($cmd, "r");
while (!eof($fp)) {
$fileName = fgets($fp);
echo "Found a file: $fileName<br>";
}

pclose($fp};

Johan

[amelhedi]

i tryed ur eg it doesn t work
"undefined function: eof()"

Johan Näsholm wrote:

Hi,

I prefer to use a shell command for this. Run the find-command and grep for .mp3 and use PHP to collect the output.

$cmd = "find * | grep .mp3"
$fp = popen($cmd, "r");
while (!eof($fp)) {
$fileName = fgets($fp);
echo "Found a file: $fileName";
}

pclose($fp};

Johan

[Anon]

Oh, my mistake. That should be feof (I also found some more errors now that I have actually tested my code ;-)

$cmd = "find /path/to/mp3s/* | grep \".mp3\"";
$fp = popen($cmd, "r");
while (!feof($fp)) {
$fileName = fgets($fp, 1024);
echo "Found a file: ".basename($fileName)."<br>";
}
pclose($fp);

The call to basename strips the path from the path+filename in $fileName.

Johan

[amelhedi]

Now the code seems to work,
But i steel have no result

First i m running PHP 4.04 under Win 2k
I think that ur code should work under unix
maybe i m wrong, I steel don t understand this point.

I already get this prob with perl under Win

I know it s better if i unstall Linux but i m just a beginer

So let consider that "path/to/mp3s/" is "D:\2pac" what ll be the code,

Thanx

[Anon]

Indeed the code works under Linux. Since you use Windows we'll try another approach. I have this snippet that will read the contents of a directory and print it. With some modifications you sould be on your way.

$d = dir("d:\2pac");
while ($entry = $d->read()) {
$pathEntry = $d->path."/".$entry;
if (is_file($pathEntry))
echo $entry."<br>\n";
else if (is_dir($pathEntry))
echo "<b>".$entry."</b><br>\n";
else
echo "<i>".$pathEntry."</i><br>\n";
}

Johan

[amelhedi]

Actualy this code is running well execpt for
$d = dir("d:\2pac");
it should be $d = dir("d:/2pac/");

but my aim was to applicate a function on each file found.

the function is not ready yet but it should be something like

create a mysql table or an array with the
File name
File size
path of the file
...
...
of each file found

so i don t think that the function above can do it cause it just print a result of a dir command if I m not wrong.

If any body have an idea about it plz let me know.

Johan Näsholm wrote:

Indeed the code works under Linux. Since you use Windows we'll try another approach. I have this snippet that will read the contents of a directory and print it. With some modifications you sould be on your way.

$d = dir("d:\2pac");
while ($entry = $d->read()) {
$pathEntry = $d->path."/".$entry;
if (is_file($pathEntry))
echo $entry."\n";
else if (is_dir($pathEntry))
echo "<b>".$entry."</b>\n";
else
echo "<i>".$pathEntry."</i>\n";
}

Johan

[watski]

I did not say it would take you all the way. Inside the while loop you can do anything with the files found.

$pathEntry is the path to the file
$entry is the file name (though not obvous 🙂
filesize($pathEntry ."/". $entry) returns the size of the file and so on.

Johan