Take the wrong file...

[ulrikqk]

Help me, help me,

I have make a little script! It can upload picture to my server, but it take the wrong picture!

If the user want to upload "c:\picture\1.jpg" then the script on the server seen like this:

copy ("c:\picture\1.jpg", "tofile");

• but the server take the file on the server place c:\picture\1.jpg, not c:\picture\1.jpg from the user!

How can I say to the server, that I want the c: on the users drive?????

[Anon]

Too bad you can't directly read a user's file... It would be so convenient to spy people. Look at this :

www.php.net/manual/features.file-upload.php

[ulrikqk]

Okay, but I have funded this:

<FORM ENCTYPE="multipart/form-data" ACTION="URL" METHOD=POST>
<INPUT TYPE="hidden" name="MAX_FILE_SIZE" value="1000">
Send this file: <INPUT NAME="userfile" TYPE="file">
<INPUT TYPE="submit" VALUE="Send File">
</FORM>

But what shall there stand in the URL file?

[Anon]

URL is your PHP script, of course !

[ulrikqk]

Yes of course!

But MUST there stand something specially in it? It wouldn´t upload something. Can you give me some courcecode please? I cannot understand my own problem!

[Anon]

Oh, I hadn't understood your question. The file is already uploaded when your script begins. Look at the help page I gave you and try :

<b>$userfile - The temporary filename in which the uploaded file was stored on the server machine.</b>

And a bit further :

<b>copy($userfile,"/place/to/put/uploaded/file");</b>

[Anon]

Hello Olivier,

But $userfile is empty, have I a problem in php4.ini?

Ulrik Q K