image button

[Anon]

hi!

i've a form with 2 image-buttons:

<input type=image name="forward" src="img/forward.gif" value="forward">
<input type=image name="backward" src="img/backward.gif" value="backward">

in my php-script i've to know wich button was pressed, but i dont know how to handle this, cos the parameters are 'forward.x', 'forward.y' ... and this are not valid variable-names.

i think i've to parse the url on my own, but i dont know how to get it.

tia
finger

[smarlowe]

Don't toture yourself with lots of extra code. The way image buttons work (according to the spec at www.w3.org anyway) is that they are like little x/y grid maps, and you are getting back the x/y offset of the click of the mouse, stored in your mouse's name. The value you set is ignored, as value is not a valid parameter for an image button.

The good news is, you can just test to see which button was pressed like this:

if (isset($forward)) $dir="forward";
else if (isset($backward)) $dir = "backward";
else $dir="unset";

Since we don't care what actual value the buttons carry, we can just test to see if they've been set, and in the event the form gets submitted via a method other than our buttons, we may want to have a default setting to handle that.

[Anon]

great thanks - it works 🙂

finger

[lereu]

scott,

I'm running into a similar problem as Tia, and I wasn't able to use the "isset" function to determine if my var was sent. It does not appear to be recognized.

[Anon]

Try this:

print implode(":",array_keys($HTTP_POST_VARS));

or $HTTP_GET_VARS if you are using a GET method form.

[lereu]

Great solution! Thank you!