small problem with for(.....)

[Anon]

Hi there!

I have following for sentence (don't work):

for($i=0; $i < $total_ques; $i++){
print "<tr><td>Question $i</td>";
printf ("<td>%s</td></tr>", $myrow["question$i"]);
}

total_ques comes from mysql database.
If i write for loop like:

for($i=0; $i < 5; $i++){

then it works fine!
Why doesn't $total_ques work in for loop??
When I print the value of $total_ques it works but in the for loop it wont't work!? WHY?? Please help me!!

[finger]

are you sure that $total_gues is a numeric
value? check it by quoting it in echo:
echo "'$total_ques'";

finger

[Anon]

I checked it and it is numeric.

[Anon]

if I print the following:

printf("<td>questions:</td><td>%s</td></tr>", $myrow["total_ques"]);

It prints (for example)

questions: 5

but when I use $total_ques at for loop:

for($i=1; $i<=$total_ques; $i++){
print "<tr><td>Kysymys $i</td>";
printf ("<td>%s</td></tr>", $myrow["question$i"]);
}

it prints nothing!!!
How can I use the $total_ques at for loop?

[finger]

sorry to say that, but IMHO you cant be
absolutely sure that its numeric by your
test.

f.e. THAT works:

$n = 5;

for ($i = 0; $i <= $n; $i++)
{
echo "$i<br>";
}

that shows that you dont have anything to
do with the var for using it as loop-var.
if its numeric. maybe you get a string, that
casually contains a number-string. check it
out by echo "'$number'"; (dont forget the
single-quotes).

regards
finger

[Anon]

I have the solution!

$total = $myrow["total_ques"];

for($i=1; $i<=$total; $i++)

and that works fine!

[finger]

well i thought that $total_quest is already
a variable you fetched out of the array 🙂