Problem with Creating String Name Loop

andrewm

Ok this is hard to explain, but I'll give it a go.

I have a table with 100+ rows that have a few text boxes in them. Each text box's name includes its row (ex. url45)

When the form is submitted I have a while loop and it submits each row (its nessecary for how I am doing this) but I can't create the string name. For instance lets say its going thru the loop and it has counted up to 23, how can I have a string that has the name $url23, but contains the information from what was $url23 submitted on the form. So far I have tried soemthing like:

$storeurl = $url . $counter
(but that obviously doesn't work and returns just 23, becuase there is no variable $url)

$storeurl = "\$url" . $counter;
(that stores $url23 as text, it does not grab the information from the varible $url23)

This is hard for me to explain so I hope you understand, if you don't let me know, cause I can't figure this out!

Thanks A LOT,
Andrew

fetak

Try this:
<?php

$counter = 5;
$variable_string = "url$counter";

$$variable_string = "this some string ;-)";

?>

After running this variable $url5 will contain string "this is some string ;-)";

              Milan Mlynarcik

andrewm

I need it the other way

I already have something stored to $url5 and I need to grab it!

Anon

Hi Andrew,

maybe it works with eval() ... sort of:

$url23='the test';
$counter=23;
$storeurl = "\$url" . $counter;
eval ("\$storeurl = $storeurl;");
echo $storeurl;

this returns "the test" ... hope thats what you needed ...
cya Rob

andrewm

thanks a lot man!

if you are curious I am using it on my site:
http://www.pbreview.com/

Thanks again!
Andrew

fetak

Touch this:
<?php

$url5 = "http://some_url/";
$url6 = "http://some_other_url/";
$number = 6;
$content ${"url".$number};

?>
$content will contain after run this : "http://some_other_url/".
It's same as that one I wrote before ... it needs just some additional changes. It's up to you. And it's faster than eval() ;-)