dynamic menu

Anon

Let me first say that I am new to php so if I make a mistake you know why. I have a page that that I am using fast templates for. I have an array to produce a dynamic menu. The problem I have is that it only displays the last result in the loop. Here is my code. Any help or pointers would be greatly appreciated. Thanks in advanced.
$site_pages = array ("index",
"about",
"contact",
"port"
);
$site_titles = array ("Home",
"about us",
"contact us",
"portfolio"
);
$page = getenv ("SCRIPT_NAME");
$page = basename ($page);
$page = str_replace (".php3", "", $page);
for ($i = 0; $i < count ($site_pages); $i++) {$mymenu="<a href=$site_pages[$i].php3>$site_titles[$i]</a>";}

$tpl->assign( array(MENUITEMS => $mymenu ));
ok thats that, what am I doing wrong?

arnihr

Well... I haven't seen ALL the code but I think I've found atleast one mistake in this code...

$page = getenv ("SCRIPT_NAME");
$page = basename ($page);
$page = str_replace (".php3", "", $page);

should really be
$page = getenv ("SCRIPT_NAME");
$page .= basename ($page);
$page .= str_replace (".php3", "", $page);

If you're adding basename($page) and the str_replace to $page which is getenv(scriptname)...

Try changing it, if it doesn't work, simply post again 🙂

I don't know about this thing right here:
$mymenu="<a href=$site_pages[$i].php3>$site_titles[$i]</a>";

Doesn't $mymenu have to be array for holding this? like $mymenu[] = "<a href...>"; ?

Whatever, maybe I'm fullofit... 🙂

Hope it helped, Arni

Anon

I have made this change to the code and now I get a value of Array displayed.
for ($i = 0; $i < count ($site_pages); $i++) {$mymenu = array("<a href=$site_pages[$i].php3>$site_titles[$i]</a>");}

$tpl->assign( array(MENUITEMS => $mymenu ));

Any Suggestions?

And as for the code that Arni wasnt sure about looked like this.
echo"<a href=$site_pages[$i].php3>$site_titles[$i]</a>";}
but I need that line to echo inside of this statment for fast templates.
$tpl->assign( array(MENUITEMS => $mymenu ));
I have assigned the $mymenu to the fasttemplate{MENUITEMS} any suggestions on what i should do. I need MENUITEMS to display the menu because in my template I have it marked {MENUITEMS} where I want the menu diplayed. I hope all this makes sense.

Anon

Don,

I think you might need to change:
$mymenu = array(
to
$mymenu .= array(

Since you are looping through and concating the string $mymenu.

Anon

ok we are getting some where now. now since I added the dot it displays ArrayArrayArrayArray. Which is good since i have four pages listed in the array. Now I need it to display the values ie home about us. Thanks allot for all you help so far.

Anon

I got it figured out now the code reads
for ($i = 0; $i < count ($site_pages); $i++) {$mymenu.="<a href=$site_pages[$i].php3>$site_titles[$i]</a>";} all because the stupid dot! well thanks for all the help!

arnihr

as I said, $mymenu[] = ...
that should've done the trick... 🙂
but I'm not 100% sure so...
I guess we'll never find out! :]

Anon

The best way to avoid this kind of mistakes try to indent your code properly, and use foreach instead of a for loop.

The ArrayArrayArrayArray thing usually
indicates that you're trying to put an
element of an array in a string by referring
to it via an array. It doesnt work, since
php parses the value of $site_pages first and
not $site_pages[$i].

foreach variant:
$i = 0;
foreach ( $site_pages as $page )
{
$mymenu
.= "<a href=$page.php3>"
. "".$site_titles[$i]."</a>";
$i++;
}

note that the foreach control structure is not yet available in php3, but in php4 it is.

good luck 🙂