Converting string to array?

I'm sure this is a very stupid question, but I'm completely stumped... I've got:

$string = 1234;

But, I need to turn that string into an array -- something like this:

$array[0] = 1
$array[1] = 2
$array[2] = 3
$array[3] = 4

I think explode might be what I'm looking for, but I'm not sure.

reads subject line Noo! Not string, variable... It's too late to think, evidently.

Where $string = 1234, $string[1] = 1, $string[2] = 2 etc...

ie:

$string = 1234;

for ($i=1;$i<=strlen($string);$i++) {
echo $string[$i];
}

will print "1234"

Unfortunately, that didn't work for me... It loops four times, but doesn't output anything.

Wouldn't $string have to be an array? I thought I'd figured it out with something like this:

$string = 1234;
$new = explode(' ', chunk_split($string, 1));
$i = 0;
while ($i < strlen($string)) {

echo "<img src=\"$new[$i].jpg\">; // this is a counter...

echo $new[$i];
$i++;
}

But that just printed 1 2 3 4 on the first loop, then didn't output anything after that... Any ideas?

/*
For all i can see here the variable
$string
is actually not a string but an integer ?

in that case a simple and very trivial way to let it work is this way:
*/

$string = 1234;
$variable = &$string; // just to avoid inconvenience :-)

$variable = "" + $variable; // converts into string, and string is actually an array of characters

foreach ( $string as $char )
$array [ 0 ] = $char;

/*try it.
it might not be what your looking for.

good luck

drm
*/

You should look into strval(), that might help you out.

$var = 12345;
$array = array();

for ($x = 0; $x < strlen(strval($var)); $x++)
$array[] = substr(strval($var), $x, 1);

This works perfectly. 🙂 I'm still a bit confused on strval() though... The manual page didn't clarify too much for me -- no comments.. Thanks!

You should look into strval(), that might help you out.

$var = 12345;
$array = array();

for ($x = 0; $x < strlen(strval($var)); $x++)
$array[] = substr(strval($var), $x, 1);