Constructing a Variable name for an IF?

Anon

Hi I have some code that Im Having Difficulty with:
if ( "$"."Question".$nbrow == $Correct ) {
$score++;
}
This code is to check the contents of the Variable Correct agains another Variable which is Called QuestionX where X is an incremented number. Is there anyway to do this in PHP, or alternatively is it possible to take every peice of data passed in and place it in an Array as I know how to navigate through an Array without any problems.
Thanx everyoen

simon_belak

try sprintf() or eval() to get the var name:

sprintf("$Question%d",$nbrow);

Anon

Use variable variables, like this:

if ( ${"Question".$nbrow} == $Correct ) {
$score++;
}

Hope that helps!

Chris King

harlan

You could use "variable variables" in this situation, but why? Why are you using all these millions of different variables with numbers tacked on the end instead of an ARRAY?

There's no advantage to
$variable1, $variable2
over
$variable[1], $variable[2]

plus your "if" statement is a cinch like that.

Anon

I Managed to get it with the variable variables, The reason that I cant put them in an array is because they are values from Option Buttons on a previous form, the number of option buttons is dependant on the number of entries in the database and there is no way to feed them into an array from what I can see, however my project is finished with the exception of one thing so thanks for your help everyone