count number of X in string?

[mrdance]

If I don´t want to build an array, is there any function for counting number of a certain character in a string?

Thanks , Henrik

[[deleted]]

Two options jump to mind:
one, use preg_match (which builds an array but that's life)

two, copy the string to a new var, and replace everything that's not the char you want, with nothing.
The strlen of the remaining string is the number of times the char was in the string.

[mrdance]

I want to find all % and get the number before them. I want to search till I can't find anymore, but it´s seems like it can't stop searching, so I belive that I have to find the nummer of % and then but it in a loop. Is there any way to solve it in a WHILE loop? Here's the code;

$disksout= file($file);
$disksout=implode($disksout,"");
("\n",",",$disksout);
//$disksouttext=fgetss($disksout, 255);
echo $disksout;
$count=10;
for ($i=0; $i<=$count; $i++)
{
if (!$offset)
{
$offset=0;
}

$pos=strpos ($disksout, "%", $offset);
$pos=$pos-2;
$result[]= substr($disksout, $pos, 2);
$offset=+$pos+3;
}

[[deleted]]

Have a good long look at what you are doing here.

for ($i=0; $i<=$count; $i++)
{
if (!$offset)
{
$offset=0;
}
$pos=strpos ($disksout, "%", $offset);
$pos=$pos-2;
$result[]= substr($disksout, $pos, 2);
$offset=+$pos+3;
}

[mrdance]

I don't see it.. 🙁 I'm sorry..

Commented;

// count is the input for how many %-signs the string contains. Usually between 5 and 10
for ($i=0; $i<=$count; $i++)
{
// if no $offset value exist, begin with pos 0
if (!$offset)
{
$offset=0;
}
// search for %, starting at the offset
$pos=strpos ($disksout, "%", $offset);
// go back to character to get the the two-digit percentnumber
$pos=$pos-2;
// store the result in an array
$result[]= substr($disksout, $pos, 2);
// increase the offset to be able to search from the lastest position
$offset=+$pos+3;
}

The problem is that it searches over and over again. There is no way to tell stop it. Any help would be appreciated; The file looks like this;

---

01-02-22 17:12

Filesystem kbytes used avail capacity Mounted on
/dev/md/dsk/d0 13270379 4952202 8185474 38% /
/dev/dsk/c2t0d0s3 13242748 5058602 8051719 39% /vol1
/dev/dsk/c2t0d1s3 13242748 2001001 11109320 16% /vol2
/dev/dsk/c2t0d2s3 13242748 2001001 11109320 16% /vol3
/dev/dsk/c2t0d3s3 13242748 2001001 11109320 16% /vol4

[[deleted]]

This is exactly why I usually ask what people are using routines for.

What you are doing is "doing things the hard way"

What you ahve there is a string with several lines, and a fixed number of columns.
So, use explode() to get an array of vars with one line in each var.
Then, go through all the elements in the array,
and explode each line around the spaces.
That gives you an array containing the 6 "words" on the line.
Print var number 4, and you've got it.

It sounds like a lot of work, but it's much clearer than going around finding the percent sign, moving back and forth etc.

[Anon]

Hi what about

$number = substr_count( pattern , $string);

or maybe

for($i=0 ; $i < strlen($string); $i++)
{
$character = $string[$i];
if ($character==" what you want"){
counter++;
}
}

Sorry if it isnt what you meant.

Allen

[mrdance]

thanks for your ideas!

/ Henrik

[[deleted]]

substr_count. I really ought to update my local copy of the manual.

thanks!

[mrdance]

substr_count was good, but I should be the other way round;

substr_count(string, pattern)

Thanks