Unseen Parse Error

[Anon]

Who's eyes here are better than mine? Please help!

<?
$conn = mysql_connect("*****", "***", "****") or die("Could not connect");
mysql_select_db("***", $conn);
$result = mysql_query("SELECT FROM forums", $conn) or die("Invalid query");

//list all the forums

while ($current = mysql_Fetch_Array($result)) {

$counter = mysql_query("SELECT * FROM topics WHERE forum='$current[name]'", $conn);
$numtopics = mysql_num_rows($counter);
$numpages = $numtopics / 20;
if($numpages % 20 = 0)
{
	$numpages++;
}
echo "<BR><BR><FONT SIZE=+1><A HREF='http://forum.levx.net/topicview.php?forum=".$current[name]."&page=".$numpages."&addpost=no'>".$current[number].". ".$current[name]."</A><BR></FONT>";
echo "<FONT SIZE=-1>".$current[description]." (Moderators : ".$current[moderators].")</FONT>";

}

?>

[[deleted]]

if($numpages % 20 = 0)

should be

if($numpages % 20 == 0)

[Anon]

Incidentally, this type of error can be avoided by reversing the comparison operands.

if(0 == $numpages % 20)

Granted it's prety awkward for people used to the "normal" way but it's a safer way of programming, especially in php where you don't have a compiler that'll spit out warnings to you.

[Anon]

Oh! Heh, sorry bout that.

I thought PHP was different from C++, with the double-everything logic signs.

[[deleted]]

Good point, but PHP does spit an error when you do 1=2 :-)
Also, what many people forget is that PHP too has a high level of error reporting available.
Use:
error_reporting(E_ALL);

and you'll get more warnings and error than you'd like.