Checkbox won't be detected

[tinuviel]

I have a page that has this checkbox and an if statement. As you can see, the checkbox is defaulted to be checked so value should be "ON", but it always goes into the else loop and displays for me that $delete_link is null. What am I doing wrong? Thanks!

<input type="checkbox" name="delete_link" value="ON" checked
<?PHP if($delete_link == 'ON'){$action_url = 'in if';}else {$action_url = 'in else';}
?>

Thanks in advance, Tin

[hawleyj]

Try simply
<input type="checkbox" name="delete_link" checked>

<?PHP

if(isset($delete_link)){

$action_url = 'in if';

}else{

$action_url = 'in else';

}
?>

Should work.

Jim

[tinuviel]

OK, I've had to change it. It is now a Radio button with 3 choices. But it will not set the the value until AFTER you click on the submit button. So I can't say for the action of the form go here if this choice or go here if that choice. Is there anyway to set the action of a form based on a radio button choice in the form?

[Anon]

You'd really need to add some javascript in the header as a function to do this kind of work.

[edwardsbc]

More generically, you are trying to do CLIENT side scripting. PHP is SERVER side scripting.

[tinuviel]

Ahhhh, OK, this makes sense. In that case, that is a breeze. Thanks!

Craig Edwards wrote:

More generically, you are trying to do CLIENT side scripting. PHP is SERVER side scripting.