day of the date

[Anon]

$date = "2001-03-16";
$dayname = date('d',$date);

echo $dayname;

This is should display Fri

and

$date = "2001-03-16";
$dayname = date('l',$date);

echo $dayname;
This should display Friday.

But i am getting problem whatever date i give it always displays Thu or Thursday.

I want to get the name of the day whatever day i put.
Can anybodyy help me.

Thanks

Chanderjit

[Anon]

It seems to be a problem with date format. You use MySQL date format in date() function. It is incorrect. I copy from manual now, and I know it works - I have used it:

echo date ("l", mktime (0,0,0,16,3,2001));

In mktime() you set:
mktime(0,0,0, $day, $month, $year). Hope it helps.

[Anon]

Thanks Annchen

I have tried this also.

When i used this it is giving me some strange outputs.

with echo date ("l", mktime (0,0,0,16,3,2001));

It gives wednesday.

with echo date ("l", mktime (0,0,0,18,3,2001));
It gives Monday.

I have tried with many more but i am getting some other day name..

I am trying some more.

Please help its urgent.

Thanks

Chanderjit

[Anon]

Oh @!#$

I gor my mistake silly mistake

The proper syntax is this
echo date ("D", mktime(0,0,0,3,19,2001));

I was putting ("D",mktime(0,0,0,19,3,2001));

The date should be before month

Thnaks

Chanderjit

[Anon]

:-)