Include classes only if needed?

[Anon]

Hey everyone -

Is anyone aware of a way to do this? I've got a somewhat extensive object/class hierarchy (in the manner in which classes include/require each other), and most of the classes are only needed if the user calls a function that uses them (which usually won't happen with many on one page view).

So...I want to save as much downloading time as possible...that code can add up. Is there any way to only include a class only if a function is called which needs it? I know I would use include_once(), but I can't just include a whole class in the middle of another class's function.

Thanks!

-Jeremy

[daarius]

yes, you can. just do include_once() inside the function which needs it. else if the function is not called. the code will not be included.

i am using this method too. and it works fine.

[Anon]

Daarius -

I tried that, but I got the error that I can't have nested classes in the code. You don't have that problem? I just put the call to include_once() as the first line in the class function, and pass in the name of the other class file ("Bar.php", let's say) as the argument.

class Foo
{
function useOtherClass()
{
include_once("Bar.php");
}
}

Then, since it's just putting the other class right in there, I get the nested classes error.

-Jeremy

[daarius]

strange..... it works perfectly fine for me. unless, this isnt causing the error that you get, and its been caused by something else. perhaps where you call the functions from imported class etc.

i am calling something like 3 to 5 classes inside a function and use them all, and i never had any problem. i suggest the error is something else.

what exaclty does your code does anyway?

[Anon]

Hi,

It would help if we could see the calls you are making.Classes are tricky at best somtimes.

COPE

[Anon]

include_once was introduced in php4