Time????Date???

[Anon]

Greetings all,
Ok here it is. Im writing a program (timesheet) and need to display the date of all the days (mon-sun) for the week prior to the current week.?????

for example today is march 16 Friday,
I need to display all last weeks days and respective dates

Mon tues wed thurs fri sat sun
3/5 3/6 3/7 3/8 3/9 3/10 3/12

HOW can this be done??

HELPPPPPP

thanks

pete

[Anon]

You might pop over to the php.net manual on date(). There are lots of user contributed code snippets that should give you ideas.

[Anon]

How about:

if(!isset($date)) $date = time();

$fdayoweek = date("w", $date);
$fdayprevweek = $date - ((($fdayoweek - 1) + 7) * 86400);

$i = $fdayprevweek;
while($i<$fdayprevweek + 604800) {
print date("D m/d", $i)."<br>";
$i = $i+86400;
}

[Anon]

Louie your a god....

Ok so that gives me the previous week. NOW how can I use that to get the present week starting on monday?

Ive almost got it but you wont believe what it looks like. Im gonna finagel with you code. THANKS>

if you have an idea on the new ? id take the help!

thanks again!!

peter

[Anon]

Okay

if(!isset($date)) $date = time();

$fdayoweek = date("w", $date);
$fdayprevweek = $date - ((($fdayoweek - 1) + 7) 86400);
$fdaythisweek = $date - (($fdayoweek - 1) 86400);

$i = $fdayprevweek;
while($i<$fdayprevweek + 604800) {
print date("D m/d", $i)."<br>";
$i = $i+86400;
}

$j = $fdaythisweek;
while($j<$fdaythisweek + 604800) {
print date("D m/d", $j)."<br>";
$j = $j+86400;
}

exit;

[Anon]

Sniff sniff I love you man!

THANKS a million!!!!!!!!!!!!!